设实数x,y满足x^2+4y^2+2x-4y+2=0,
(x+1)²+(2y-1)²=0;
x+1=0;
x=-1;
2y-1=0;
y=1/2;
则x^2y+2x的值等于(-1)²×(1/2)+2×(-1)
=1/2-2
=-3/2;
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设实数x,y满足x^2+4y^2+2x-4y+2=0,
(x+1)²+(2y-1)²=0;
x+1=0;
x=-1;
2y-1=0;
y=1/2;
则x^2y+2x的值等于(-1)²×(1/2)+2×(-1)
=1/2-2
=-3/2;
很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,