2sin2x*cos2x如何化简为-2sin4x
2个回答
因为2sinxcosx=sin2x
2sin2xcos2x=sin4x
你题是不是打错了
相关问题
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
cos^4 x-sin^4 x+2 sin^2 x化简
化简cos^4x+sin^2xcos^2x+sin^2x
化简sin^4x-sin^2+cos^2
化简f(x)=(√(sin(x/2))^4+4(cos(x/2))^2))-(√(cos(x/2))^4+4(sin(x
化简:2sin^4x+3\4sin^2(2x)+5cos^4x-1\2(cos4x+cos2x)
1、化简函数f(x)=(sin^4 x+cos^4 x+sin^2 xcos^2 x)/(2-sin2x)
sin2x-2cos^2(x)/sin(x-π/4)化简,过程详细
化简:2cos2x+2sin^2 x+cos(-x)分之sin2x+sin(π-x)=___________
化简sin^4x+cos^2x