Question

O是直线A.B上一点OC.OD是从O点引出的两条射线OE平分角AOC,角BOC:角AOE:角AOD=2：5:8求角BOD

Answer 1

设∠AOE=x

∠AOC=2∠AOE=2∠EOC=2X,

∠BOC:∠AOE:∠AOD=2:5:8,∠AOD=8x/5,∠BOC=2x/5,

∠AOC=∠BOC=180,所以：x=75

所以：∠AOC=150,∠AOD=120,∠BOC=2x/5=30,

∠BOD=180-∠AOD=60度