a² + √2ab + b²
= a² + √2ab + (√2b/2)² + b²/2
= (a +√2b/2 )² + b²/2
= (a +√2b/2 )² - (bi)²/2
= (a +√2b/2 + b i /2) (a +√2b/2 - b i /2)
式中的 i 为虚数单位.
在实数范围不可以分解.
a² + √2ab + b²
= a² + √2ab + (√2b/2)² + b²/2
= (a +√2b/2 )² + b²/2
= (a +√2b/2 )² - (bi)²/2
= (a +√2b/2 + b i /2) (a +√2b/2 - b i /2)
式中的 i 为虚数单位.
在实数范围不可以分解.