f(m+n)=f(m)+f(n)-1,则有
f(0+0)=f(0)+f(0)-1,
f(0)=1.
而,f(1/2)=2,
f[1/2+(-1/2)]=f(1/2)+f(-1/2)-1=f(0),
1=2+f(-1/2)-1,
f(-1/2)=0.