(x²-x)²-8x²+8x+12
=(x²-x)²-8(x²-x)+12
=[(x²-x)-2][(x²-x)-6]
=(x²-x-2)(x²-x-6)
=(x+1)(x-2)(x+2)(x-3)
(x²-x)²-8x²+8x+12
=(x²-x)²-8(x²-x)+12
=[(x²-x)-2][(x²-x)-6]
=(x²-x-2)(x²-x-6)
=(x+1)(x-2)(x+2)(x-3)