Question

计算x2+y2+2xy分之x2-4y2/x2+xy分之2y+x

Answer 1

(x²+y²+2xy)分之(x²-4y²)/(x²+xy)分之(2y+x)

=(x+y)²分之[(x+2y)(x-2y)]/[x(x+y)]分之(x+2y)

=(x+y)²分之[(x+2y)(x-2y)]×(x+2y)分之[x(x+y)]

=(x+y)分之[x(x-2y)]

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