折射率为1.5的玻璃上,覆盖了一层厚度均匀的油膜(n=1.30),单色平面光垂直照射在油膜上,若所用光源的波长可以连续变

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  • 2ne = (2k1+1)λ1/2 = (2k2+1)λ2/2

    把波长代入 (2k1+1)*500/2 = (2k2+1)*700/2

    得 k1 = 3 ,k2 = 2

    2ne = (2*3+1)*500/2

    e = 673.077 nm