设公比为q
已知S6/S3=[a1*(q^6-1)/(q-1)]/[a1*(q^3-1)/(q-1)]
=(q^3+1)(q^3-1)/(q^3-1)
=q^3+1=4
q^3=3
所以S12/S6=[a1*(q^12-1)/(q-1)]/[a1*(q^6-1)/(q-1)]
=(q^6+1)(q^6-1)/(q^6-1)
=q^6+1
=(q^3)²+1
=3²+1
=10
设公比为q
已知S6/S3=[a1*(q^6-1)/(q-1)]/[a1*(q^3-1)/(q-1)]
=(q^3+1)(q^3-1)/(q^3-1)
=q^3+1=4
q^3=3
所以S12/S6=[a1*(q^12-1)/(q-1)]/[a1*(q^6-1)/(q-1)]
=(q^6+1)(q^6-1)/(q^6-1)
=q^6+1
=(q^3)²+1
=3²+1
=10