Question

常微分方程 y' = a*y^2 +b*y +c

Answer 1

y' = a*y^2 +b*y +c

dy/dx=a*y^2 +b*y +c

dy/a*y^2 +b*y +c=dx

1/[根号（ac-b^2)]arctan(y+b/2a)=x+D,(D为常数)

y=tan[(x+D)*根号（ac-b^2)]-b/2a,(D为常数)

楼主验证一下,应该是对的!