(5y+1)(5y^2-5y+1)-5(1+2y)(1-2y)
2个回答
原式=25y³-25y²+5y+5y²-5y+1-5+20y²
=25y³-4
相关问题
5y+1乘5y平方-5y+1-5乘1+2y乘1-2y
5y²_(y_2)(3y+1)_2(y+1)(y-5)过程
化简:f(y)=(25y^2-5y+1)(5y+1)-5(1-4y^2)
解方程:y/5-(y-1)/2=1-(y+2)/5
若x1^2+5x2^2=10,x2y1-x1y2=5,x1y1+5x2y2=15,求y1^2+5y2^2
{x/3-y=5 (1) {x/4-y=1 (2) {5x+2y=5 (1) {2x+5y=8 (2)
4(y-2-(5[1-2y]-4[5y-1[)=0
4(y-2)- {5(1-2y)- 4(5y-1)}=0.
(y+2)(y-2)--(y-1)(y+5)
-(-2y+1)-(5-4y)-(+5)其中y=-2