Question

f(x)=ax^2+bx+c,f'(0)>0,恒有f(x)>=0,求f(1)/f'(0)最小值

Answer 1

f'(x)=2ax+b

f'(0)=b

f(1)=a+b+c

f(1)/f'(0)=(a+b+c)/b

f(1)/f'(0)最小值=b/b=1