Question

已知室温时,0.1mo1/L某一元酸HA在水中有0.1％发生电离

Answer 1

HA ===可逆=== H+ + A-

0.1*(1-0.1%) 0.1*0.1% 0.1*0.1%

K===c(H+)*c(A-)/c(HA)==0.10.1%*0.10.1%/[0.1(1-0.1%)]==0.1%*0.1%/0.1===1×10^-7