Question

在523K时,将0.110mol PCl5(g)引入1L容器中,建立下列平衡：PCl5(g)=PCl3(g)+Cl2(g

Answer 1

PCl5(g)=PCl3(g)+Cl2(g)

0.11 0 0

0.05 0.05 0.05

0.06 0.05 0.05

K={PCl3}{Cl2}/{PCl5}=0.05x0.05/0.06=1/24mol/L

转化率为0.05/0.11乘以100%=