Question

已知函数F(x)=|X^2-X-6|若对任意X1,X2属于[t,t+1]且x1不等于x2,都有f(x1)-f(x2)/x

Answer 1

因为对任意X1,X2属于[t,t+1]且x1不等于x2,都有f(x1)-f(x2)/x1-x2＞0,所以F(x)在[t,t+1]为增函数,又因为F(x)在[-2,1/2],[3,+无穷]为增函数,所以t>=-2,t+1=3,解得-2=