Question

-3x平方+4xy+10y平方 因式分解

Answer 1

3x^2+4xy-2y^2 =(1/3)(9x^2+12xy-6y^2) =(1/3)[(3x)^2+2×(3x)(2y)+(2y)^2-(2y)^2-6y^2] =(1/3)[(3x+2y)^2-(√10y)^2] =(1/3)(3x+2y+√10y)(3x+2y-√10y)