已知大圆弧弦长L1=540,弧高H1=200,半径R1=282,同心小圆弧与大圆弧上下距离均为34,求小圆弧弦长L2,弧高H2公式?
小圆弧半径为R2.
R1^2=(R1-H1)^2+(L1/2)^2
R1^2=R1^2-2*R1*H1+H1^2+L1^2/4
2*R1*H1=H1^2+L1^2/4
R1=H1/2+L1^2/(8*H1)
=200/2+540^2/(8*200)
=282.25
R2=R1-34=248.25
H2=H1-2*34=200-68=132
L2=2*(R2^2-(R2-H2)^2)^0.5
=2*(248.25^2-(248.25-132)^2)^0.5
=477.87