Question

已知（a-2^2)+(b+1^2)=0,求多项式3a^2b+ab^2-3a^2b+5ab+ab^2-4ab+2/1 ab

Answer 1

应该是(a-2)^2+(b+1)^2=0,a=2,b=-1,

3a^2b+ab^2-3a^2b+5ab+ab^2-4ab+2/1 ab^2=5/2a^2b+ab=5-2=3