1.先观察式子1+4=2•(1+4/2) 1+4+7=3•(1+7/2) 1+4+7+10=4&

3个回答

  • 1.1+4+7+……+(3n-2)=n*[1+(3n-2)/2] n是数的个数,3n-2是最后一个数.

    2.(z-x)²-4(x-y)(y-x)=(z-x)²+4(x-y)(x-y)=(z-x)²+4(x-y)²=0

    两个数的平方和为0,那么这两个数为0,所以,z-x=0 x-y=0 所以,x=y=z,所以,x-2y+z=x-2x+x=0.

    3.(1)x²+1/x²=(x+1/x)²-2*x*1/x=(x+1/x)²-2=9-2=7

    (2)x^4+1/x^4=(x²+1/x²)²-2*x²*1/x²=7²-2=47

    4.(1)x²+y²=(x+y)²-2xy=16+24=40

    (2)x²-xy+y²=x²+y²-xy=40-(-12)=52

    (3)(x-y)²=x²-2xy+y²=x²+y²-2xy=40-2(-12)=64

    5.(x+3)/(x²-9)+3/(x-3)=(x+3)/(x+3)(x-3) +3/(x-3)=1/(x-3)+3/(x-3)=4/(x-3) 把x=1带入,得 原式=4/(-2)=-2