(X²+1)/5x+(5x)/(X²+1)=5/2
设(X²+1)/5x=y
原方程转化为
y+1/y=5/2
2y²+5y+2=0
(2y+1)(y+2)=0
y=-1/2
y=-2
当y=-1/2时
(X²+1)/5x=-1/2
2x²+2=-5x
2x²+5x+2=0
(2x+1)(x+2)=0
x=-1/2 x=-2
当y=-2时
(X²+1)/5x=-2
x²+10x+1=0(方程无实数解)
经检验原方程的根是x=-1/2 x=-2
(X²+1)/5x+(5x)/(X²+1)=5/2
设(X²+1)/5x=y
原方程转化为
y+1/y=5/2
2y²+5y+2=0
(2y+1)(y+2)=0
y=-1/2
y=-2
当y=-1/2时
(X²+1)/5x=-1/2
2x²+2=-5x
2x²+5x+2=0
(2x+1)(x+2)=0
x=-1/2 x=-2
当y=-2时
(X²+1)/5x=-2
x²+10x+1=0(方程无实数解)
经检验原方程的根是x=-1/2 x=-2