Question

怎样化简这个式子?s/(s/2v1+s/2v2),具体化简过程.我还是不懂啊= = 化简不来啊。

Answer 1

s/(s/2v1+s/2v2)

=s/[（v1+v2）s/2v1v2]

=s*2v1v2/[（v1+v2）s]

=2*v1v2/(v1+v2)

那我没办法了