f(x)=√3*(1-cos2x)-(sin2xcosπ/3-cos2xsinπ/3)=√3-√3cos2x-1/2sin2x+√3/2*cos2x=√3-√3/2*cos2x-1/2*sin2x=√3-sin(π/3+2x)∵x∈[-π/2,0]∴π/3+2x∈[-2π/3,π/3]∴sin(π/3+2x)∈[-1,√3/2]∴f（x)∈[√3...
f(x)=2根号3sin^2x-sin(2x-π/3)
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