设A和B在左准线上射影分别为C和D,|FB| = x,
作BT⊥AC于T,则有|AT| = |AC| - |BD| = x/e
|AB| = |AF| + |BF| = 3x,在直角三角形ABT中有:
|AT| = |AB|cos 60°,即x/e = 3x/2.
所以离心率e = 2/3.
设A和B在左准线上射影分别为C和D,|FB| = x,
作BT⊥AC于T,则有|AT| = |AC| - |BD| = x/e
|AB| = |AF| + |BF| = 3x,在直角三角形ABT中有:
|AT| = |AB|cos 60°,即x/e = 3x/2.
所以离心率e = 2/3.