若sina+cosa=tana 0度

1个回答

  • sin a + cos a = tan a

    sin a + cos a = sin a / cos a

    sin a .cos a + cos a .cos a = sin a

    sin a .cos a + 1 - sin a .sin a = sin a

    cos a = (sin a .sin a + sin a - 1)/sin a

    cos a = sin a + 1 - 1/sin a

    0°< a < 180° => 0 < sin a =< 1

    若 a = 90°,sin a = 1,

    那么 cos a = 1 + 1 - 1 = 1

    矛盾!

    sin a + 1 = 1/sin a

    sin a .sin a + sin a = 1

    sin a .sin a + sin a - 1 = 0

    sin a = ( -1 + √5)/2

    a = 38.17°或 141.83°

    若 0°< a < 38.17° 或 141.83°< a < 180°,

    sin a + 1 < 1/sin a,

    cos a < 0

    ∵ 当 90°< a < 180°时,-1 < cos a < 0

    ∴ 141.83°< a < 180°

    若 38.17°< a < 141.83°,

    sin a + 1 > 1/sin a,

    cos a > 0

    ∵ 当 0°< a < 90°时,0 < cos a < 1

    ∴ 38.17°< a < 90°

    => a 的范围:38.17°< a < 90°及 141.83°< a < 180°