(1)-3(x+1)²=-6
（x+1）²=-6/-3
x+1=±√2
x=±√2-1
x=-√3,x=1
(2)1/4x²+x=2
x²+4x=8
x²+4x+(2)²=8+4
(x+2)²=12
x+2=±2√3
x=±2√3-2
x=2√3-2,x=-2√3-2
(3)y²-2y=-1
y²-2y+1²=-1+1
(y-1)²=0
y=1
(4)第4题有问题.
(5)1/4x^2-6x+3=0
x²-24x=-12
x²-24x+(12)²=-12+144
(x-12)²=132
x-12=±2√33
x=±2√33+12
x=2√33+12,x=12-2√33
(6)x^2-(3x+2)^2=0
x²-（9x²+12x+4）=0
x²-9x²-12x-4=0
8x²+12x=-4
x²+3/2x=-1/2
x²+3/2x+(3/4)²=-1/2+9/16
（x+3/4）²=1/16
x+3/4=±1/4
x=±1/4-3/4
x=-1,x--1/2