y=t/(2t+1)
===> y=[(1/2)*(2t+1)-(1/2)]/(2t+1)
===> y=(1/2)-[(1/2)/(2t+1)]
===> y-(1/2)=-(1/2)/(2t+1)
===> 2[y-(1/2)]=-1/(2t+1)
===> 2y-1=-1/(2t+1)
令2y-1=Y,2t+1=X
则,Y=-1/X(原点就是y=1/2,t=-1/2)
y=t/(2t+1)
===> y=[(1/2)*(2t+1)-(1/2)]/(2t+1)
===> y=(1/2)-[(1/2)/(2t+1)]
===> y-(1/2)=-(1/2)/(2t+1)
===> 2[y-(1/2)]=-1/(2t+1)
===> 2y-1=-1/(2t+1)
令2y-1=Y,2t+1=X
则,Y=-1/X(原点就是y=1/2,t=-1/2)