Question

方程x2+y2-2(m+3)x+2(1-4m平方)y+16m四次方+9=0表示一个圆 1.求实数m的取值范围；2.该圆的

Answer 1

x²-2(m+3)x+(m+3)²+y²+2(1-4m²)y+(1-4m²)²=(m+3)²+(1-4m²)²-16m的4次方-9

[x-(m+3)]²+[y+(1-4m²)]²=m²+6m+9+1-8m²+16m的4次方-16m的4次方-9

[x-(m+3)]²+[y+(1-4m²)]²= -7m²+6m+1

∴-7m²+6m+1>0

7m²-6m-1