Question

已知代数式x2+y2-14x+2y+50的值为0,求x与y的值.

Answer 1

化简得：(x2-14x+49)+（y2+2y+1）=0

(x-7)2+(y+1)2=0

∵（x-7）2>=0,(y+1)2>=0

∴x-7=0,y+1=0

∴x=7,y=-1