Question

若s=vt-1/2gt^2,求在t=1,t=1+△t之间的平均速度,其中△t=1,0.1,0.01

Answer 1

△S=v（t+△t）-1/2g（t+△t)^2-vt-1/2gt^2 =v△t-gt△t-1/2g△t △S/△t=v-gt-1/2g△t △t=1,△S/△t=v-gt-1/2g △t=0.1,△S/△t=v-gt-1/20g △t=0.1,△S/△t=v-gt-1/200g