Question

very easy的数学题,已知abc为△abc的三边长,且满足a²+b²-8b-10a+41=0,

Answer 1

165/8

=20.625

=20+0.625

=20+(5/8)

=(16+4)+(1/2)+(1/8)

=(2^4)+(2^2)+2^(-1)+2^(-3)

所以代入(2^a)+(2^b)+(2^c)+(2^d)

得a=4,b=2,c=-1,d=-3

把a=4,b=2,c=-1,d=-3代入（a+b+c+d-1)^2010=1