x^2-2xy+y^2+2x-2y+1怎么解,求解,谢谢
5个回答
=(x^2-2xy+y^2)+2(x-y)+1
=(x-y)^2+2(x-y)+1
=(x-y+1)^2
相关问题
求解微分方程(xy^2+x)dx+(y-x^2y)dy=0,y(2)=1的通解
x^2-xy-2y^2=0是怎么变成(x+y)(x-2y)=0求解,
解方程组:X^2+xy+y^2-2x-2y=1 Xy=2
x2—2xy=3y2 2xy+y2=1 怎么解这个方程组?
菜鸟求解微积分题.x^2y'=x^2y^2-xy的通解.
求解一道数学题;(xy-1)^2+(x+y-2)(x+y-2xy) 分解因式
求解方程Y'X^2=XY-Y^2
解方程组:(x-1)(y-2)=xy,x(x+2)-4y(y-1)=(x+2y)(x-2y)
解方程组:xy/x+y=-6(1) 2xy/x+2y=12(2)
已知1/x+1/y=2,求(x+y+2xy+2y)÷(2xy+y)的值谢谢了,