若1/x-1/y=2,求2x+xy-2y/3x-2xy-3y的值.
1个回答
若1/x-1/y=2,则
2xy=x-y
2x+xy-2y/3x-2xy-3y=(2x+0.5x-0.5y-2y)/(3x+x-y-3y)=5/8=0.625
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