对下列多项式进行因式分解``(1)2X^3+4X^2-6X (2)X^4+6X^2+8(3)X^4+5X^2-36 (4

1个回答

  • (1)2X^3+4X^2-6X

    =2X(X^2+2X-3)

    =2X(X+3)(X-1)

    (2)X^4+6X^2+8

    =(X^4+4X^2+4)+2X^2+4

    =(X^2+2)^2+2(X^2+2)

    =(X^2+2)(X^2+2+2)

    =(X^2+2)(X^2+4)

    (3)X^4+5X^2-36

    =(X^2+9)(X^2-4)

    =(X^2+9)(X+2)(X-2)

    (4) X^4-29X^2+100

    =(X^2-4)(X^2-25)

    =(X+2)(X-2)(X+5)(X-5)

    (5)(X^2+3)^2-3(X^2+3)+2

    =(X^2+3-1)(X^2+3-2)

    =(X^2+2)(X^2+1)

    (6)(X^2+X)(X^2+X-2)-3

    ==(x^2+x+1)(x^2+x-3)

    分析:

    把x^2+x看成一个整体

    比如令x^2+x=t

    原式=t(t-2)-3

    =t^2-2t-3

    =(t+1)(t-3)

    把t=x^2+x代回

    =(x^2+x+1)(x^2+x-3)