1/cos50度+tan10度=?

2个回答

  • 1/cos50°+tg10°=1/sin40° + sin10°/cos10°

    =1/sin40° +(sin10°*2sin10°) /(cos10°*2sin10°)

    =1/sin40° +2(sin10°)^2 /sin20°

    =1/sin40° +(1-cos20°) /sin20°

    =1/sin40°+(1-cos20°)*2cos20° /sin20°*2cos20°

    =[1+2cos20°-2(cos20°)^2] /sin40°

    =(2cos20°-cos40°) /sin40°

    =(cos20°+2sin30°sin10°) /sin40°

    =(sin70°+sin10°) /sin40°

    =[sin(40°+30°)+sin(40°-30°)] /sin40°

    =2sin40°cos30°/sin40°=2cos30°=√3