Question

初二分式乘法计算.（1）a^2-4 a-3———— · ————a^2-4a+3 a^2+3a+2(2)a^2-8a+1

Answer 1

(1)

(a^2-4)*(a-3)/(a^2-4a+3)(a^2+3a+2)

=(a+2)(a-2)(a-3)/(a-1)(a-3)(a+1)(a+2)

=(a-2)/(a-1)(a+1)

(2)

(a^2-8a+16)(16-a^2)/(9-a^2)(9+6a+a^2)

=(a-4)^3*(4+a)/(a-3)^2*(a+3)