好像没有北向南θ度这种说法,“between North and the direction in which he rows”我理解是他划船的角度是从北向B点方向偏θ度
划船时间为：16/cosθ/16=1/cosθ
跑步时间为：|（20^2-16^2）^0.5-16*tgθ|/12=|1-4/3tgθ|
t=1/cosθ+|1-4/3tgθ|
有绝对值是因为当θ的角度大于AB直线与正北方向夹角时,其值为负数
急求一道三角函数的应用题!A man can row at 16 km/h,and run at 12 km/h.He
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