Question

已知|2a-b+1|+(3a+3/2b)²=0,求代数式3ab+a²/a²-b²

Answer 1

因为|2a-b+1|≥0,(3a+3/2b)²≥0

所以2a-b+1=0,3a+3b/2=0

解得a=-1/4,b=1/2

代入原式得.麻烦您加几个括号

我觉得可能是

(3ab+a²)/(a²-b²)÷(a+3b)/(a-b)

=a(3b+a)/(a+b)(a-b)×(a-b)/(a+3b)

=a/(a+b)

=-0.25÷0.25=-1

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