Question

方程（|m|-1)x=(m+1)(m-2) 当m等于多少无解,当m等于多少有无数解,当m等于多少有唯一解

Answer 1

（|m|-1)x=(m+1)(m-2)

①当 |m|-1=0 且 (m+1)(m-2)≠0时,方程无解

解得m=1时方程无解

②当 |m|-1=0 且 (m+1)(m-2)=0时,方程有无数解

解得当m=-1时,方程有无数解

③当|m|-1≠0即m≠±1时,方程有唯一解