Question

已知x/(x平方+x+1)=m(m不等于0),求x平方/x四次方+x平方+1的值

Answer 1

x/(x^2+x+1)=m

1/(x+1+1/x)=m

x+1+1/x=1/m

x+1/x=1/m -1=(1-m)/m

x^2/(x^4+x^2+1)

=1/(x^2+1+1/x^2)

=1/[(x+1/x)^2-1]

=1/[(1-m)^2/m^2-1]

=m^2/(1-2m)