【初中物理】一矿泉水瓶装满水后,瓶和水的总质量为700g(矿泉水的密度为1×103kg/m3),空瓶的质量为200g

2个回答

  • 4)v瓶=(m总-m空)/p水

    =(700g-200g)/1

    =500cm³

    m某=m水+25g

    =500g+25g

    =525g

    p某=m某/v瓶

    =525g/500cm³

    =1.05g/cm³

    答:此液体密度为1.05g/cm³.

    5)m酒=(v瓶*3/4)*0.8

    =(500cm³*3/4)*0.8

    =300g

    m水=(v瓶-v水)*p水

    =(500cm³-375cm³)*1g/cm³

    =125g

    p混=(m酒+m水)/v瓶

    =(300g+125g)/500cm³

    =0.85g/cm³

    m酒瓶总=m酒+m水+m瓶

    =300g+125g+200g

    =625g

    答:酒精溶液的密度为0.85g/cm³;瓶和酒精溶液的总质量为625g.