Question

求导：f(x)=(e^x+1)/e^x

Answer 1

f(x)=(e^x+1)/e^x = 1 + 1/e^x = 1 + e^(-x)

f '(x) = [1 + e^(-x)] '

= [e^(-x)] '

=[e^(-x)]*(-x)'

=[e^(-x)]*(-1)

= -e^(-x)

= -1/e^x,即f '(x) = -1/e^x