首先y是x的函数,两边对x求导,
y'=e^x(siny-cosy)+e^x(y'*cosy+y'*siny)
y'=y+y'*e^x*(siny+cosy)
[1-e^x(siny+cosy)]*y'=y
y'=y/[1-e^x(siny+cosy)]
y=(siny-cosy)e^x,怎么求导
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