Question

已知a的平方+b的平方-6a-8b+25=0,求2a+3b的值

Answer 1

a^2+b^2-6a-8b+25=0

[a-3]^2+[b-4]^2=0

a-3=0===>a=3

b-4=0===>b=4

2a+3b=2*3+3*4=6+12=18