Question

2.56gCu跟足量的2.0mol/L稀硝酸完全反应,则

Answer 1

m=n/M=2.56/64=0.04mol

3Cu+8HNO3==3Cu(NO3)2+2NO+4H2O

3 8 2

0.04 x y

x=0.107mol v=n/c=0.107/2=0.0535L=53.5ml

y=2/75 V=n·Vm=22.4*2/75=0.60L