若双曲线x^2/a^2-y^2/b^2=1(a>0,b
3个回答
渐近线 y=(b/a)x=tana
c^2/a^2=b^2/a^2+1=seca^2
e=c/a=|seca|
相关问题
若双曲线x2/a2-y2/b2=1与双曲线x2/b2-y2/a2=1(a>0,b
双曲线 x^2/a^2-y^2/b^2 =1(a>0,b>0) 知双曲线A1A2是实轴顶
已知椭圆x^2/2a^2+y^2/b^2=1(a>b>0)和双曲线x^2/a^2-y^2/b^2=1(a>0,b>0)相
双曲线x2/a2-y2/b2=1(0
已知双曲线a^2|x^2-b^2|y^2=1(a>0,b
已知抛物线y2=2px(p>0),椭圆x2a2+y2b2=1(a>b>0),双曲线x2a2−y2b2=1(a>0,b>0
【双曲线与椭圆共焦点】的题若椭圆x^2/a^2+y^2/b^2=1(a>b>0)和双曲线x^2/m^2-y^2/n^2=
双曲线 F为双曲线C:x^2/a^2+y^2/b^2=1(a>0,b>0)的右焦点
设0<k<a2,那么双曲线x2a2−k−y2b2+k=1与双曲线 x2a2−y2b2=1有( )
设双曲线x^2/a^2-y^2/b^2=1(0