Question

如图所示,三角形ABC中,AB的垂直平分线交BC于点D,AC垂直平分线交BC于点E,若角DAE＝26°,则角BAC＝?

Answer 1

∠DAE=∠CAE+∠DAB-∠BAC

∠CAE=∠C ∠DAB=∠B

∠BAC=∠C+∠B-26°

∠BAC+∠B+∠C=180°

∠BAC=180°-∠BAC-26°

∠BAC=77°