cos20°-cos40°-cos80°的值为?

2个回答

  • cos 40 = cos(60-20) = cos60*cos20+sin60*sin20

    cos 80 = cos(60+20) = cos60*cos20-sin60*sin20

    所以

    代入原式得

    cos20-(cos60*cos20+sin60*sin20)-(cos60*cos20-sin60*sin20)

    =cos20-2cos60*cos20-sin60*sin20+sin60*sin20

    =cos20-2cos60*cos20

    =cos20-2*(1/2)*cos20

    =0;