(1-1/2)+(1/2-1/3)+(1/3-1/4)+(1/4-1/5).+(1/2005-1/2006)=1-1/2006=2005/2006
1x1/2 2x1/3 3x1/4 ……2005x1/2006 2006x1/2007
1个回答
相关问题
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2007x2006-2006x2005+2005x2004-2004x2003.+3x2-2x1
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已知2005x^3=2006y^3=2007z^3,且1/x+1/y+1/z=1,说明3√2005x^2+2006y^2
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1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+...1/(x+2005)(x+2006)
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2006x2007+2007x2008+2008x2006-2/1+2+3+4+5'''''''+2006+2007
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1/(x+1)(x+2)+1/（x+2）（x+3）.1/(x+2006)(x+2007)=?
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化简1/(x+1)(x+2)+1/(x+3)(x+4)+……1/(x+2005)(x+2006)=
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x/1*2+x/2*3+……+x/2005*2006=2005
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解方程：x/1*2+x/2*3+x/3*4+.+x/2005*2006=2005
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（1-2）x（2-3）x（3-4）x ...x（2005x2006）=多少?
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当X分别取1/2007,1/2006,.1/2,1.2005,2006,2007时,求1-X^2/1+X^2的所有值的和