Question

（2002x）2-2001×2003x-1=0求大神帮助

Answer 1

因式分解法: (2002x)^2-(2002-1)(2002+1)x-1=0,(2002x)^2-2002^2x+x-1=0, 2002^2x(x-1)+(x-1)=0, (x-1)(2002^2x+1)=0,所以 x-1=0或2002^2x+1=0,即 x=1或x=-1/4008004.