数学难题,只要第3题。高手进。(注:请用初中方法,但可以用点到直线距离公式,圆方程,两点间距离公式)谢谢。

2个回答

  • P(a,0)

    |CD|=|CF|=1

    y=(1/4)x^2+bx+c

    x=0,|OA|=y=c

    A(0,c),B(c,c),C(c,0),E(1+c,1),F(1+c,0)

    r^2=PA^2=PB^2=PE^2

    a=1,c=2

    (1)

    y=(1/4)x^2-(3/2)x+2

    P(1,0),F(3,0),G(4,0),M(3.5,0),C(2,0),|CG|=2

    (2)

    k(PE)*k(ME)=-1

    (3)

    N(x,y),C(2,0),G(4,0)

    k(NC)=y/(x-2),k(NG)=y/(x-4)

    [k(NG)-k(NC)]/[1+k(NG)*k(NC)]≤1/√3

    [y/(x-4)-y/(x-2)]/[1+y/(x-4)*y/(x-2)]≤1/√3

    2y/(x^2-6x+8+y^2))≤1/√3

    y=(1/4)x^2-(3/2)x+2=0.25x^2-1.5x+2

    4y=x^2-6x+8

    x^2-6x+8=(1/4)y=0.25y

    2y/(x^2-6x+8+y^2)

    =2y/(4y+y^2)

    =2/(4+y)

    =2/(4+0.25x^2-1.5x+2)

    =8/(24+x^2-6x)

    8/(24+x^2-6x))≤1/√3